Sandy bought \(4 \frac{\mathrm{1} }{\mathrm 2} \) pounds of apples and six kiwi fruits. Brandon bought \(3 \frac{\mathrm{1} }{\mathrm 4} \) pounds of apples and nine kiwi fruits. If apples cost $1.39 per pound and kiwis are two for $1.00, how much more money did Sandy spend than Brandon?
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Detailed Explanation
The cost of Sandy’s purchase is (\(4 \frac{\mathrm{1} }{\mathrm 2} \) × $1.39) + (6 × $0.50)= $9.26.
The cost of Brandon’s purchase is (\(3 \frac{\mathrm{1} }{\mathrm 4} \) × $1.39) + (9 × $0.50) = $9.02.
Sandy spent $9.26 – $9.02 = $0.24 more.
The cost of Brandon’s purchase is (\(3 \frac{\mathrm{1} }{\mathrm 4} \) × $1.39) + (9 × $0.50) = $9.02.
Sandy spent $9.26 – $9.02 = $0.24 more.
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