One-eighth of a bookstore’s magazines are sold on a Friday. If \(\frac{\mathrm{1} }{\mathrm{4}}\) of the remaining magazines are sold the next day, what fractional part of the magazines remains at the end of the second day?
Get all 1000+ ASVAB exam-like questions with our mobile apps!
Detailed Explanation
At the end of the first day, there are 1 - \(\frac{\mathrm{1} }{\mathrm{8}}\) = \(\frac{\mathrm{7} }{\mathrm{8}}\) of the magazines remaining.
\(\frac{\mathrm{7} }{\mathrm{8}}\) * \(\frac{\mathrm{1} }{\mathrm{4}}\) = \(\frac{\mathrm{7} }{\mathrm{32}}\) sold the next day.
So at the end of the second day, there are \(\frac{\mathrm{7} }{\mathrm{8}}\) - \(\frac{\mathrm{7} }{\mathrm{32}}\) =\(\frac{\mathrm{28} }{\mathrm{32}}\) - \(\frac{\mathrm{7} }{\mathrm{32}}\) = \(\frac{\mathrm{21} }{\mathrm{32}}\) of the magazines remaining.
\(\frac{\mathrm{7} }{\mathrm{8}}\) * \(\frac{\mathrm{1} }{\mathrm{4}}\) = \(\frac{\mathrm{7} }{\mathrm{32}}\) sold the next day.
So at the end of the second day, there are \(\frac{\mathrm{7} }{\mathrm{8}}\) - \(\frac{\mathrm{7} }{\mathrm{32}}\) =\(\frac{\mathrm{28} }{\mathrm{32}}\) - \(\frac{\mathrm{7} }{\mathrm{32}}\) = \(\frac{\mathrm{21} }{\mathrm{32}}\) of the magazines remaining.
Take more free practice tests for other ASVAB topics with our ASVAB practice test now!