What is the area of an isosceles right triangle that has one leg that measures 4 cm?
8 \(cm^2\)
16 \(cm^2\)
32 \(cm^2\)
Detailed Explanation
If the triangle is isosceles, that means its two legs are equal in length, so they are both 4. In a right triangle, the two legs are the base and the height.
The area of a triangle is equal to \(\frac{\mathrm{1} }{\mathrm{2} } bh\), so the area =\(\frac{\mathrm{1} }{\mathrm{2} } \times 4 \times 4 = 8\)\(cm^2\).
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