The population of Grand Island, Nebraska, grew by 600,000 people between 1995 and 2005, one-fifth more than the town council predicted. The town council originally predicted the city’s population would grow by

`_________`

.The population of Grand Island, Nebraska, grew by 600,000 people between 1995 and 2005, one-fifth more than the town council predicted. The town council originally predicted the city’s population would grow by

`_________`

.Detailed Explanation

To determine the town council's original prediction for the city's population growth, we can calculate one-fifth less than the actual growth of 600,000 people between 1995 and 2005. Let's denote the original predicted growth as "x." Given that the actual growth was one-fifth more than the predicted growth, we can express it as:

Actual Growth = Predicted Growth + One-Fifth of Predicted Growth

600,000 = x + (1/5)x

To solve for x, we can simplify the equation:

600,000 = (6/5)x

Dividing both sides by (6/5), we get:

x = (5/6) × 600,000

x = 500,000

Therefore, the town council originally predicted the city's population would grow by 500,000 people.

Actual Growth = Predicted Growth + One-Fifth of Predicted Growth

600,000 = x + (1/5)x

To solve for x, we can simplify the equation:

600,000 = (6/5)x

Dividing both sides by (6/5), we get:

x = (5/6) × 600,000

x = 500,000

Therefore, the town council originally predicted the city's population would grow by 500,000 people.