If a hexahedral die is rolled two times, what’s the probability of NOT rolling a five both times?
\(\frac{\mathrm{25} }{\mathrm{36}}\)
\(\frac{\mathrm{1} }{\mathrm{36}}\)
\(\frac{\mathrm{1} }{\mathrm{6}}\)
\(\frac{\mathrm{4} }{\mathrm{36}}\)
Detailed Explanation
The probability of rolling a 5 is 1 out of 6 (\(\frac{\mathrm{1} }{\mathrm{6}}\)), so the probability of NOT rolling a 5 is 1 − \(\frac{\mathrm{1} }{\mathrm{6}}\) , or 5/6 . The probability of not rolling a 5 twice is \(\frac{\mathrm{5} }{\mathrm{6}}\) × \(\frac{\mathrm{5} }{\mathrm{6}}\) , or \(\frac{\mathrm{25} }{\mathrm{36}}\) .
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