Carl's throw went: \(7 \frac{\mathrm{1} }{\mathrm{3}} × 2 \frac{\mathrm{1} }{\mathrm{2}}
= \frac{\mathrm{22} }{\mathrm{3}} × \frac{\mathrm{5} }{\mathrm{2}} = \frac{\mathrm{110} }{\mathrm{6}} = 18 \frac{\mathrm{1} }{\mathrm{3}}\)
The difference between the two throws is: \(18 \frac{\mathrm{1} }{\mathrm{3}} - 7 \frac{\mathrm{1} }{\mathrm{3}}\)
To subtract these, you need to find a common denominator, which is 3 in this case: \(18 \frac{\mathrm{1} }{\mathrm{3}} - 7 \frac{\mathrm{1} }{\mathrm{3}} = \frac{\mathrm{54} }{\mathrm{3}} + \frac{\mathrm{1} }{\mathrm{3}} - \frac{\mathrm{21} }{\mathrm{3}} - \frac{\mathrm{1} }{\mathrm{3}}\)
Now, combine the fractions: \(\frac{\mathrm{54 + 1 -21-1} }{\mathrm{3}} = \frac{\mathrm{33} }{\mathrm{3}} = 11\)
Carl's throw traveled 11 yards farther than Devin's.