Find the difference between the area of the circle and the area of the square. The area of the circle is \(πr^2 = π × 2^2 = 4π\). The area of the square is \(s^2\), where s represents the length of the square. The radius is half the length of the square’s diagonal, so the diagonal is 4. By the Pythagorean theorem, \(s^2 + s^2 = 4^2\) <=> \(2s^2 = 16\) so \(s^2 = 8\). The difference in area is 4π – 8.