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ASVAB Full-length Test
A 120 V light bulb is rated for 40 watts. What is the light bulb's current rating?
1/3 A
3 A
2 A
1 A
Detailed Explanation
P = IV, so I = P/V or \(I = \frac{\mathrm{40watts} }{\mathrm{120V} } = \frac{\mathrm{1} }{\mathrm{3}}A\)
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